Quoted from "Djed;600926"
ABCD * 4 = DCBA
What are the numbers?
Quoted from "ghostwolf82;600944"
0 is the only number that makes this equation true. The reason sperle's answer isn't able to work is (he put the numbers in the wrong order, and) he is assuming 2178*4=8712... however using Operator Precedence in the correct order, this equation becomes A*B*C*D*4 = DCBA, and when you input zero, you get 0*0*0*0*4=0000
= 8712 for that to be true then the next be true 4(2bcd) = dcb2 and next is 4(2bc
= 8cb2 then 4(21c
= 8c12 then 4(217
= 8712. no where did we say that this was a multiplication problem but more of a what does each # have to be to be equal on each side. always two ways to skin a cat
Quoted from "sperle;600994"
I think we are both right. you are presuming that abcd is a*b*c*d. I am presuming abcd is 4 numbers together.
Quoted from "ghostwolf82;601014"
The full riddle, which gives context (and makes you right), is:
If you multiply the four-digit number abcd by 4, the order of digits will be reversed. That is, abcd x 4 = dcba. The digits a, b,c and d are all different. The values are between 0-9 and each is different. Find abcd.

Quoted from "ghostwolf82;601014"
No. He is trying to use a well known math "riddle", however he failed. Which means that it is as I have said now, the answer is zero. Had he used the full riddle, then you would be right.
The full riddle, which gives context (and makes you right), is:
If you multiply the four-digit number abcd by 4, the order of digits will be reversed. That is, abcd x 4 = dcba. The digits a, b,c and d are all different. The values are between 0-9 and each is different. Find abcd.
The only other way to go about this would be with Spacial Cognition, but I have a feeling almost no one here knows a thing about that, and also involves a LOT more equations to get to the answer down that rabbit hole.
